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✨ Term 1 Maths · Chapter 2

Power Play

Fold a sheet of paper in half 46 times, and it would reach the MOON. Discover the wild power of exponents — and every law you need for the exam.

1

Folding paper to the Moon

Hi, it's Patto! Fold a piece of paper in half. Then fold it again. And again. Most people can't fold real paper more than 7 times — but let's IMAGINE we could keep going. How thick would it get after 30 folds? 46 folds? Guess first, then try the slider below!
0 folds → still 0.001 cm thick
FoldsThicknessCompare to…
17~131 cmTaller than a person!
26~671 mBurj Khalifa is 830 m
30~10.7 kmHigher than airplanes fly!
46>7,00,000 kmFarther than the Moon (3,84,400 km)!
📖 Any 10-fold span multiplies thickness by exactly 1024

Not just folds 0–10 — ANY stretch of 10 folds, from anywhere in the table, multiplies the thickness by 1024 (since 2¹⁰ = 1024). Check it below:

FoldsThickness changeTimes increased by
0 → 100.001 cm → 1.024 cm1.024 ÷ 0.001 = 1024
10 → 201.024 cm → 10.485 m10.485 m ÷ 1.024 cm = 1024
20 → 3010.485 m → 10.737 km10.737 km ÷ 10.485 m = 1024
30 → 4010.737 km → 10995 km10995 km ÷ 10.737 km = 1024

That's the magic of exponential growth: it doesn't matter WHERE you start counting — every 10 more folds always multiplies by the SAME 1024×, because 2ᵃ⁺¹⁰ ÷ 2ᵃ = 2¹⁰ = 1024 for any starting point a.

💡 The big idea: exponential growth

Every fold doubles the thickness. Doing this over and over is called multiplicative (exponential) growth — and it explodes MUCH faster than you'd expect. Compare: building a ladder to the Moon with 20 cm rungs needs 1.9 BILLION rungs (adding, one at a time) — but paper-folding gets there in just 46 doublings! Multiplying beats adding, every time, in the long run. (We'll work out exactly how to get that 1.9 billion number in Section 6!)

2

The laws of exponents

nᵃ means n multiplied by itself a times. In 5⁴=625, 5 is the base and 4 is the exponent (or "power").

⚠️ Don't mix up ×3 and to-the-power-3!

4+4+4 = 3×4 = 12 (repeated ADDING), but 4×4×4 = 4³ = 64 (repeated MULTIPLYING) — totally different results from the same three 4's!

Each fold DOUBLES the thickness, so after 10 folds we multiply the initial thickness v by 2, ten times over — that's 2¹⁰ multiplied by v.

(v) 2¹⁰v is correct. (iv) is close but forgets to multiply by v; the others (10v, 10+v, 2×10×v, 10²v) all describe ADDING or a fixed multiple, not repeated doubling.

🎮 Try the exponent calculator

to the power
Try base 3, power 4 to start!
💎 The riddle of the shining stones

A king has 3 daughters, each with 3 baskets, each basket has 3 keys opening 3 rooms, each room has 3 tables with 3 necklaces, each necklace has 3 diamonds!

3×3×3×3×3×3×3 = 3⁷ = 2187 diamonds
Notice: 3⁷ = 3⁴ × 3³ (81 × 27 = 2187) — this is the Product Rule!

Split each exponent into two smaller pieces that add up to it, then multiply the two smaller powers:

2⁹ = 2⁴ × 2⁵ = 16 × 32 = 512 5⁷ = 5³ × 5⁴ = 125 × 625 = 78125 4⁶ = 4² × 4⁴ = 16 × 256 = 4096

There's more than one valid split for each one — e.g. 2⁹ = 2³×2⁶ works too. As long as the two exponents add up to the original, the answer comes out the same!

Rule nameFormula
Product Rulenᵃ × nᵇ = nᵃ⁺ᵇ
Power of a Power(nᵃ)ᵇ = nᵃ×ᵇ
Power of a Productnᵃ × mᵃ = (nm)ᵃ
Quotient Rulenᵃ ÷ nᵇ = nᵃ⁻ᵇ
💡 Password combinations use this too!

A 5-digit passcode (0–9) has 10⁵ = 1,00,000 possibilities. A 6-letter password (A–Z) has 26⁶ = 30,89,15,776 possibilities! Every time you make independent choices in a row, you MULTIPLY the number of options.

🔑 Practice: prime factors & tricky bases

Keep dividing by the smallest prime that fits, until you reach 1:

32400 = 2×2×2×2 × 5×5 × 3×3×3×3

32400 = 2⁴ × 5² × 3⁴

A negative number multiplied an ODD number of times stays negative; an EVEN number of times, the minus signs cancel in pairs and it turns positive.

(−1)⁵ = −1 (negative, since 5 is odd). (−1)⁵⁶ = 1 (positive, since 56 is even).

(−2)⁴ = (−2)×(−2)×(−2)×(−2) = 4 × 4 = 16

Yes, (−2)⁴ = 16. Four negatives multiplied together (an even count) give a positive answer.

0² = 0×0 = 0 0⁵ = 0×0×0×0×0 = 0

0ⁿ = 0, for any n > 0 — multiplying zero by itself any number of times still gives zero! (The one exception is 0⁰, which is left undefined — that's actually WHY we said n can't be 0 back when we defined n⁰ = 1.)

(i) 6×6×6×6 = 6⁴ (ii) y×y = y² (iii) b×b×b×b = b⁴ (iv) 5×5×7×7×7 = 5² × 7³ (v) 2×2×a×a = 2² × a² (vi) a×a×a×c×c×c×c×d = a³ × c⁴ × d
648 = 2³ × 3⁴ 405 = 3⁴ × 5 540 = 2² × 3³ × 5 3600 = 2⁴ × 3² × 5²
(i) 2×10³ = 2000 (ii) 7²×2³ = 49×8 = 392 (iii) 3×4⁴ = 3×256 = 768 (iv) (−3)²×(−5)² = 9×25 = 225 (v) 3²×10⁴ = 9×10000 = 90000 (vi) (−2)⁵×(−10)⁶ = (−32)×1000000 = −32000000

Watch the signs! An odd power of a negative number stays negative.

🪷 The Magical Pond

A pink lotus sits in a magical pond. The number of lotuses DOUBLES every day, and after 30 days the whole pond is fully covered.

On which day was the pond exactly half full? Since the count doubles each day, the day before "full" must have been "half" — so the pond was half covered on day 29.

Fully covered (day 30): 2³⁰ lotuses Half covered (day 29): 2²⁹ lotuses

Now imagine a SECOND pond where the lotus count TRIPLES every day. Damayanti grows a lotus in the doubling pond for 4 days (giving 1×2×2×2×2 = 2⁴ lotuses), then moves all of them into the tripling pond for 4 more days.

After first 4 days (doubling pond): 2⁴ lotuses After next 4 days (tripling pond): 2⁴ × 3⁴ lotuses

If Damayanti had done it the OTHER way round (tripling first, then doubling), she'd get 1×3⁴×2⁴ = 2⁴×3⁴ — the SAME answer! Regrouping the factors: 2⁴×3⁴ = (2×3)⁴ = 6⁴.

Big idea: mᵃ × nᵃ = (mn)ᵃ — same power, different bases, multiply the bases together!
📖 Try it: 2⁵ × 5⁵, and 10⁴ ÷ 5⁴

Using mᵃ × nᵃ = (mn)ᵃ: 2⁵ × 5⁵ = (2×5)⁵ = 10⁵ = 1,00,000. And using the matching division rule mᵃ ÷ nᵃ = (m÷n)ᵃ: 10⁴ ÷ 5⁴ = (10÷5)⁴ = 2⁴ = 16.

👕 How Many Combinations?

Estu has 4 dresses and 3 caps. For EACH cap, he could wear any of the 4 dresses — so the total outfits is 4+4+4 = 4×3 = 12.

Roxie has 7 dresses, 2 hats, AND 3 pairs of shoes. Every independent choice multiplies together:

Roxie's outfits = 7 × 2 × 3 = 42 ways

Now imagine a lock with digits 0–9. A 2-digit lock has 10×10 = 100 passwords. A 3-digit lock has 100×10 = 1000 passwords. Following the pattern up to a 5-digit lock:

5-digit lock passwords = 10×10×10×10×10 = 10⁵ = 1,00,000

And Estu's dream lock with 6 slots using letters A–Z (26 choices per slot) would have 26⁶ = 30,89,15,776 possible passwords!

Independent choices in a row → MULTIPLY the number of options each time.
3

Zero & negative powers

📖 The Quotient Rule: nᵃ ÷ nᵇ = nᵃ⁻ᵇ

Just like erasing half a line of length 2⁴ repeatedly (halving = dividing by 2 each time) leaves 2⁴ ÷ 2³ = 2¹, dividing ANY power of the same base just SUBTRACTS the exponents.

2¹⁰⁰ ÷ 2²⁵ = 2¹⁰⁰⁻²⁵ = 2⁷⁵

Just subtract the exponents (100 − 25 = 75) — no need to actually multiply out either giant number!

🤔 What happens when you divide a power by itself?
2⁴ ÷ 2⁴ = 2⁴⁻⁴ = 2⁰

But ANY number divided by itself is 1 (as long as it's not 0)…

So n⁰ = 1, for any n ≠ 0! (n can't be 0, since that would mean 0÷0, which is undefined.)
📖 Negative exponents = "flip it over"

2⁴ ÷ 2⁵ = 2⁻¹, but direct division gives 16 ÷ 32 = 1/2. So 2⁻¹ = 1/2! In general: n⁻ᵃ = 1/nᵃ. A negative exponent doesn't mean a negative number — it means "flip to make a fraction"!

⚠️ These rules work for ANY integers, not just positive whole numbers!

All the laws of exponents (product, power-of-power, quotient) work exactly the same way even when the exponents are zero or negative.

Using n⁻ᵃ = 1/nᵃ — just "flip" the base to the bottom of a fraction and make the exponent positive:

2⁻⁴ = 1/2⁴ 10⁻⁵ = 1/10⁵ (−7)⁻² = 1/(−7)² (−5)⁻³ = 1/(−5)³ 10⁻¹⁰⁰ = 1/10¹⁰⁰
2⁻⁴ × 2⁷ = 2³ = 8 3² × 3⁻⁵ × 3⁶ = 3²⁻⁵⁺⁶ = 3³ = 27 p³ × p⁻¹⁰ = p⁻⁷ 2⁴ × (−4)⁻² = 16 × 1/16 = 1 [since (−4)²=16] 8^p × 8^q = 8^(p+q)

Same base multiplying? ADD the exponents — even when some of them are negative or letters!

📏 Power Lines: seeing all the powers on one line

Let's line up ALL the powers of 4, from tiny fractions to huge numbers, and watch the ×4 pattern march right through zero!
PowerValue
4⁻²1/16
4⁻¹1/4
4⁰1
4
16
64
4⁴256
4⁵1024
4⁶4096
4⁷16384
4⁸65536

Every step UP the line multiplies by 4; every step DOWN divides by 4. That's why 4⁻² = 1/16 keeps following the same rule as the positive powers — nothing "breaks" at zero!

Yes! Since 4⁷ ÷ 4⁵ = 4², and 16384 ÷ 1024 = 16 = 4². ✓

4² is 4⁴ times larger than 4⁻² (because 4² ÷ 4⁻² = 4⁽²⁻⁽⁻²⁾⁾ = 4⁴ = 256).

Now here's the same idea with base 7 — use this power line to answer the questions below.

PowerValue
7⁻⁴1/2401
7⁻³1/343
7⁻²1/49
7⁻¹1/7
7⁰1
7
49
343
7⁴2401
7⁵16807
7⁶117649
7⁷823543
2,401 × 49 = 7⁴ × 7² = 7⁶ = 117649 49³ = (7²)³ = 7⁶ = 117649 343 × 2,401 = 7³ × 7⁴ = 7⁷ = 823543 16,807 ÷ 49 = 7⁵ ÷ 7² = 7³ = 343 7 ÷ 343 = 7¹ ÷ 7³ = 7⁻² = 1/49 16,807 ÷ 8,23,543 = 7⁵ ÷ 7⁷ = 7⁻² = 1/49 1,17,649 × 1/343 = 7⁶ × 7⁻³ = 7³ = 343 1/343 × 1/343 = 7⁻³ × 7⁻³ = 7⁻⁶ = 1/117649
4

Powers of 10

We already write big numbers in "expanded form" using place value — 47561 = (4×10000) + (7×1000) + (5×100) + (6×10) + 1. Now that we know exponents, we can write EVERY place value as a power of 10:

47561 = (4×10⁴) + (7×10³) + (5×10²) + (6×10¹) + (1×10⁰)
172 = (1×10²) + (7×10¹) + (2×10⁰) 5642 = (5×10³) + (6×10²) + (4×10¹) + (2×10⁰) 6374 = (6×10³) + (3×10²) + (7×10¹) + (4×10⁰)
📖 What about numbers with a decimal point?

Digits AFTER the decimal point use NEGATIVE powers of 10 — the tenths place is 10⁻¹, the hundredths place is 10⁻², and so on.

561.903 = (5×100) + (6×10) + 1 + (9×1/10) + (0×1/100) + (3×1/1000). Writing every part as a power of 10:

561.903 = (5×10²) + (6×10¹) + (1×10⁰) + (9×10⁻¹) + (0×10⁻²) + (3×10⁻³)

Notice how the negative exponents count DOWN past zero, exactly like the Power Lines you saw earlier!

5

Scientific notation

Writing huge numbers with lots of zeros is error-prone — miss one zero and ₹5,000 becomes ₹50,000! Scientific notation fixes this.

📖 The rule: x × 10ᵡ

Any number can be written as x × 10ᵡ, where 1 ≤ x < 10 and y is any integer. Example: 5900 = 5.9 × 10³. The exponent y roughly tells you the SIZE of the number; x fine-tunes the exact value.

⚠️ The exponent matters MORE than the first digit!

Mumbai's population, 2×10⁷, changing to 3×10⁷ only grows it by half (2 crore → 3 crore). But changing the EXPONENT from 2×10⁷ to 2×10⁸ makes it 10 times bigger (2 crore → 20 crore)! That's why standard form always writes out the exponent — it tells you the true "size" of the number.

📖 How many coefficient digits should you actually keep?

If Kohima's population is exactly 1,42,395, writing it in scientific notation gives the impression we're SURE of every single digit, right down to the units place.

But often we only know a number roughly — and the number of digits we keep in the coefficient x tells the reader how confident we are:

Sure only that it's "around 1 lakh 42 thousand"? → 1.42 × 10⁵ Sure only that it's "around 1 lakh 40 thousand"? → 1.4 × 10⁵

MORE digits in the coefficient = MORE precision claimed. Fewer digits = a rougher, more honest estimate. Always match the digits you keep to how well you actually know the number!

🌌 Real distances in our solar system
Sun → Earth: 1.496 × 10¹¹ m Sun → Saturn: 1.4335 × 10¹² m Saturn → Uranus: 1.439 × 10¹² m
Smallest distance = Sun–Earth (10¹¹ is smaller than 10¹²)!
Distance to galaxy centre: 3 × 10²⁰ m Stars in our galaxy: 1 × 10¹¹ Mass of the Earth: 5.976 × 10²⁴ kg

This is exactly WHY scientific notation exists — counting all those zeros by eye is a recipe for mistakes!

🌍 Getting a feel for REALLY big numbers

How many ants are on Earth? How long ago did humans first appear? Numbers this big are hard to picture — but powers of 10 let us line them all up and compare.

PowerReal-world fact
10⁰Northern white rhinos left in the world (both female): 2
10¹Hainan gibbons alive (2024): about 42 (≈4×10¹)
10²Kakapo parrots alive (2025): 242 (≈2×10²)
10³Komodo dragons in the world (all in Indonesia): fewer than 3000 (≈3×10³)
10⁴Maned wolves (mostly Brazil, 2005 estimate): over 17,000 (≈1.7×10⁴)
10⁵African elephants (2018): ≈4.15 lakh (≈4×10⁵)
10⁶American alligators (2025): ≈50 lakh / 5 million (5×10⁶)
10⁷Global camels: over 3.5 crore (3.5×10⁷). Global horses: ≈5.8 crore (5.8×10⁷)
10⁸Water buffaloes worldwide: over 20 crore (2×10⁸), mostly in Asia
10⁹Global starlings: ≈1.3 arab/billion. World's HUMAN population (2025): 8.2 arab/billion (8.2×10⁹)
10¹⁰Global chickens alive at any time: ≈33 billion (3.3×10¹⁰)
10¹²Trees on Earth (2023): ≈30 kharab / 3 trillion (3×10¹²)
10¹⁴Mosquitoes worldwide (2023): ≈11 neel / 110 trillion. Antarctic krill: ≈50 neel / 500 trillion (5×10¹⁴)
10¹⁵Beetles worldwide: ≈1 padma/quadrillion. Earthworms: also ≈1 padma/quadrillion
10¹⁶ANTS worldwide: ≈20 padma / 20 quadrillion (2×10¹⁶) — ants alone outweigh all wild birds and mammals combined!
10²¹Grains of sand on all beaches & deserts on Earth (enough for every ant to have 10 tiny sand castles!)
10²³Stars in the observable universe: ≈2×10²³
10²⁵Drops of water on Earth: ≈2×10²⁵ (at 16 drops per millilitre)

With a global human population of ≈8×10⁹ and ≈4×10⁵ African elephants, that's roughly 20,000 people for every single elephant!

⏱️ Getting a feel for time, using powers of 10 seconds

SecondsReal-world comparison
10⁰Time for a ball thrown up to fall back down (a few seconds)
10¹One full blood-circulation through the body (10–20 s); a traffic-signal wait
10²Time to make a cup of tea (5–10 min); light takes ~8 min to reach Earth from the Sun
10³A satellite in low Earth orbit takes ~90 min–2 hr for one full revolution
10⁴Time to digest a meal (2–4 hr); lifespan of an adult mayfly (~a day)
10⁷Time spent sleeping in a year (~4 months); Mangalyaan took 298 days (≈2.65×10⁷ s) to reach Mars
10⁸Typical dog lifespan: 3–15 years (≈3.17×10⁸ s)
10⁹Halley's comet orbital period: 75–79 years, next return 2061 (≈2.4×10⁹ s)
10¹⁰The Chola dynasty ruled for 900+ years (3rd C. BCE–12th C. CE)
10¹¹Oldest living tree: ~5000 years; time since the last peak ice age (19,000–26,000 yrs ago)
10¹²Homo sapiens first appeared 2–3 lakh years ago
10¹³Steppe Mammoth appeared roughly 8–18 lakh years ago
10¹⁵Age of the Himalayas: ~5.5 crore years; dinosaurs went extinct 6.6 crore years ago
10¹⁷Earth is 4.5 billion years old; the Milky Way formed 13.6 billion years ago; the Universe is ~13.8 billion years old (≈4.3×10¹⁷ s)
💡 Fun fact: ants outweigh us!

There are roughly 20 quadrillion ants on Earth — that's about 2.5 million ants for every single human! Together, ants weigh more than all wild birds and mammals on Earth combined.

Ants per human = (2×10¹⁶) ÷ (8×10⁹) = 2.5 × 10⁶ ants Starling flocks = (1.3×10⁹) ÷ 10⁴ = 1.3 × 10⁵ flocks
Total leaves = 3×10¹² × 10⁴ = 3 × 10¹⁶ leaves Moon distance in cm = 3,84,400 km × 1,00,000 = 3.844×10¹⁰ cm Sheets needed = 3.844×10¹⁰ ÷ 0.001 = 3.844 × 10¹³ sheets

Compare that to just 46 FOLDS of a single sheet reaching the Moon — that's the incredible power of doubling (exponential growth) versus simply stacking sheets one at a time!

🎂 A different way to say your age!

🎈 How old, REALLY?

Estu asks Roxie how old she is. "I completed 13 years a few weeks ago!" she says — but then, just for fun, she answers again: "I'm 4840 days old today!"

Every day has 24 hours, so multiply:

4840 days × 24 hours/day = 1,16,160 hours old

Count 4070 days backward from today. 4070 days is 4070 ÷ 365.25 ≈ 11.1 years, so go back about 11 years, then fine-tune day by day:

4070 days before 30 August 2026 = 9 July 2015

So Estu's date of birth works out to roughly 9 July 2015 (using today, 30 Aug 2026, as the reference date — your exact answer will shift depending on what "today" is when you solve it!).

💡 Try it yourself: if you'd lived exactly 1 million seconds, how old would you be?

A million seconds is only about 11.6 days — barely a week and a half! (See the reveal near the end of Section 8 for the full working.)

6

Did you ever wonder?

This is the FUN part — using powers of 10, guessing, and reasonable assumptions to estimate answers to real "how big / how long / how many" questions. This kind of quick, reasoned estimating is sometimes called a Fermi estimate.
📖 The 3-step estimating method

1. Guess — make an instinctive guess with NO calculation.

2. Model — describe the relationship between the quantities you need, and make reasonable assumptions for anything unknown.

3. Compute — do the maths, and see how close your guess was! Your assumptions can vary from someone else's — that's okay, as long as they're reasonable.

🙏 Tulabhara: donating your own weight

Tulābhāra is an old Southern-Indian tradition of donating goods equal to a person's own body weight, as a token of gratitude. Nanjundappa wants to donate jaggery equal to Roxie's weight (she's 13) and wheat equal to Estu's weight (he's 11).

Worth of jaggery (₹) = Roxie's weight (kg) × cost of 1 kg jaggery Worth of wheat (₹) = Estu's weight (kg) × cost of 1 kg wheat

Assuming Roxie ≈ 45 kg and jaggery ≈ ₹70/kg: worth of jaggery = 45 × 70 = ₹3150. Assuming Estu ≈ 50 kg and wheat ≈ ₹50/kg: worth of wheat = 50 × 50 = ₹2500.

These are ESTIMATES — different reasonable assumptions give different (but still sensible) answers!

A ₹1 coin weighs about 4–5 grams (say 4.5 g = 0.0045 kg). Number of coins needed:

45 kg ÷ 0.0045 kg per coin = 10,000 coins (order of 10⁴)

That's TEN THOUSAND coins just to match one 13-year-old's weight! (Your answer may differ slightly depending on the coin weight you assume — that's fine.)

Assume an adult weighs ≈60 kg. If each notebook weighs ≈100 g (0.1 kg) and goes to one student:

Notebooks = 60 kg ÷ 0.1 kg = 600 notebooks → could help ~600 students

For annadāna, if one meal weighs ≈0.5 kg: 60 ÷ 0.5 = 120 meals — enough to feed roughly 120 people that year. (Again — reasonable assumptions, your numbers may vary!)

Assume a comfortable walking pace of about 20 km/day (walking several hours, with rest):

400 km ÷ 20 km/day = 20 days

So they'd have set out roughly 20 days earlier. (If they walked faster — say 25–30 km/day — it could be closer to 13–16 days; estimates like this depend on your assumed pace.)

Before modern transport, people travelled entire lifetimes on foot — merchants, sages, and scholars walked thousands of km across deserts, mountains, and rivers.

1. Guess first — would it be less than once around? A few times? Dozens of times?

2. Model: Total distance walked = walking speed × hours walked per day × days walked per year × number of years. Then divide by 40,000 km to get the number of times around the Earth.

3. Compute — assuming a steady walking pace of ≈5 km/h, for about 8 hours a day, on roughly 300 days a year (allowing for rest, bad weather etc.), over a 60-year walking "career":

Total distance = 5 km/h × 8 h/day × 300 days/yr × 60 yr = 7,20,000 km Times around Earth = 7,20,000 km ÷ 40,000 km = 18 times

So a person could walk around the Earth roughly 18 times in a lifetime! (Your own assumptions about pace, hours, and years may reasonably give something a bit different — that's fine, as long as your reasoning is sound.)

🪜 The ladder to the Moon: linear vs. exponential growth

Roxie tells Estu about a sci-fi story where people build a LADDER all the way to the Moon. "I wonder — if we really had a ladder like that, how many steps would it have?"

To find out, we need the gap between rungs. Let's assume a reasonable 20 cm between each step, and the Earth–Moon distance is 3,84,400 km.

3,84,400 km = 3,84,40,000 m = 3,84,40,00,000 cm Number of steps = 3,84,40,00,000 cm ÷ 20 cm = 1,92,20,00,000 steps = 192 crore 20 lakh steps ≈ 1.92 billion steps
⚠️ Linear growth vs. exponential growth

Climbing the ladder ADDS 20 cm at a time — that's called linear growth (additive). It takes a whopping 1,92,20,00,000 steps to reach the Moon that way. But folding a piece of paper DOUBLES its thickness each time — exponential growth (multiplicative) — and reaches the very same Moon in just 46 folds! Multiplying beats adding by an almost unimaginable margin.

Linear (ladder): 20 + 20 + 20 + ... (1,92,20,00,000 times) Exponential (folding): 0.001 × 2 × 2 × 2 × ... (46 times)
7

A pinch of history

How far back does exponential thinking go? Thousands of years, it turns out!

📖 The Lalitavistara — a 1st-century-BCE Buddhist treatise

In a dialogue between the mathematician Arjuna and Prince Gautama (the Bodhisattva), we find number-NAMES for odd powers of ten all the way up to 10⁵³! "A hundred kotis is an ayuta (10⁹), a hundred ayutas a niyuta (10¹¹), a hundred niyutas a kankara (10¹³) … a hundred vibhutangamas is a tallakshana (10⁵³)." Other Indian texts go even further — the Amalasiddhi names powers up to 10⁹⁶, and a Pali grammar text names powers up to a staggering 10¹⁴⁰!

🇮🇳 How the Indian naming system builds up

RelationshipAs a calculationPower of 10
A hundred thousand is a lakh100 × 100010⁵
A hundred lakhs is a crore100 × 10⁵10⁷
A hundred crores is an arab100 × 10⁷10⁹
A hundred arab is a kharab100 × 10⁹10¹¹
A hundred kharab is a neel100 × 10¹¹10¹³
A hundred neel is a padma100 × 10¹³10¹⁵
A hundred padma is a shankh100 × 10¹⁵10¹⁷
A hundred shankh is a maha shankh100 × 10¹⁷10¹⁹

🌐 The international (American) system

RelationshipAs a calculationPower of 10
A thousand thousand is a million1000 × 100010⁶
A thousand million is a billion1000 × 10⁶10⁹
A thousand billion is a trillion1000 × 10⁹10¹²
A thousand trillion is a quadrillion1000 × 10¹²10¹⁵
quintillion10¹⁸
sextillion10²¹
septillion10²⁴
octillion10²⁷
nonillion10³⁰
decillion10³³

Each prefix is a Latin/Greek counting word: quad=4, quint=5, sext=6, sept=7, oct=8, non=9, dec=10.

It tells you how many groups of "thousand" (10³) are multiplied on top of a million (10⁶). E.g. quadrillion = 10⁶ × (10³)⁴⁻¹ = 10¹⁵ — the prefix number is basically the count of thousands beyond the first one.

💡 The googol and the googolplex

The number 10¹⁰⁰ is called a googol (yes, that's where the company "Google" got its name from!). For comparison, scientists estimate there are only about 10⁷⁸ to 10⁸² atoms in the entire observable universe — a googol is far bigger than that.

A googolplex is 10googol — 10 raised to the power of a googol! It's so large that writing out all its zeros would need more space than exists in the observable universe.

India's highest-value note today is ₹2000. But history has seen far wilder numbers:

  • Hungary, 1946: a note valued 1 sextillion pengő (10²¹, called "1 milliard b.-pengő") was printed but never actually issued.
  • Zimbabwe, 2009: a real, issued 100 trillion (10¹⁴) Zimbabwean dollar note — worth only about $30 at the time it was printed, due to hyperinflation!

Both are dramatic real-world reminders of why scientific notation matters — these are numbers no one could safely write out digit by digit!

8

Every question from the book

Cover the answer, try it yourself first, then tap to check!
648 = 2³ × 3⁴ 3600 = 2⁴ × 3² × 5²

One new container of 5 bottles arrives EACH day — so after 40 days there are 40 containers, each holding 5 bottles. This is ADDING containers (not multiplying), so:

Total bottles = 5 × 40 = 200 = 2 × 10² bottles

64 = 2⁶, so 64³ = 2¹⁸. Splitting the exponent 18 different ways (or splitting the base):

64³ = 2¹⁰ × 2⁸ = 4⁵ × 4⁴ = 8³ × 8³ 192⁸: exponent 8 splits as 2⁴⁸ × 3⁸ = 2⁴⁰ × 2⁸ × 3⁸ = 2⁴⁰ × 6⁸ 32⁻⁵ = 2⁻²⁵: 2⁻¹⁰ × 2⁻¹⁵ = 2⁻⁵ × 2⁻²⁰ = 4⁻¹² × 2⁻¹

There are lots of correct ways to split these — as long as multiplying the pieces back together gives the original number!

7¹⁵ = (7³)⁵ = (7⁵)³ 8⁶ = (8²)³ = (2³)⁶ = 2¹⁸ [since 8 = 2³] 9¹⁴ = (9²)⁷ = (3²)¹⁴ = 3²⁸ [since 9 = 3²] 5⁸ = (5²)⁴ = (5⁴)²

Each one has more than one right answer — just make sure the two exponents in your split MULTIPLY to give the original power (e.g. for 7¹⁵: 3×5=15 either way)!

2⁻⁴ × 2⁷ = 2³ = 8 p³ × p⁻¹⁰ = p⁻⁷
59,853 = 5.9853 × 10⁴ 65,950 = 6.595 × 10⁴ 34,30,000 = 3.43 × 10⁶ 70,04,00,00,000 = 7.004 × 10¹⁰

10⁹ = 1,000,000,000 — that's LESS than 8.5 billion, so 9 digits isn't enough.

10¹⁰ = 10,000,000,000 — enough!

At least 10 digits are needed.

Yes, infinitely many! They're exactly the 6th powers (n⁶), since n⁶ = (n³)² = (n²)³ — always both a square AND a cube at once. Examples: 1, 64, 729, 4096…

(i) Only Sometimes True. It's true only for 6th powers (like 64=4³=8²), but 27=3³ is a cube that is NOT a square.

(ii) Always True. A fourth power n⁴ = (n²)² — which is always a square number.

(iii) Always True. Since n⁵ ÷ n³ = n⁵⁻³ = n², a whole number — so n⁵ always divides evenly by n³.

(iv) Always True. (n₁)³ × (n₂)³ = (n₁×n₂)³ — still a perfect cube.

(v) Never True. q⁴⁶ is a 4th power only if 46 is divisible by 4, and a 6th power only if 46 is divisible by 6 — but 46÷4=11.5 and 46÷6≈7.67, neither divides evenly, so q⁴⁶ (q prime) is NEVER both.

Rewrite 4³² as 2⁶⁴, so:

2²²⁴ ÷ 2⁶⁴ = 2¹⁶⁰

Units digits of powers of 2 repeat in a cycle of 4: 2,4,8,6, 2,4,8,6… Since 160 ÷ 4 = 40 exactly, 2¹⁶⁰ has the same units digit as 2⁴ (=16).

Units digit = 6

2⁴×3⁶ = 16 × 729 = 11,664 6⁴×3² = 1296 × 9 = 11,664 6¹⁰ ≈ 6.05 × 10⁷ (way bigger — NOT equal) 18²×6² = 324 × 36 = 11,664 6²⁴ ≈ 4.7 × 10¹⁸ (astronomically bigger — NOT equal)

2⁴×3⁶, 6⁴×3², and 18²×6² are all equal (all = 11,664) — because rewriting each in terms of the SAME prime factors (2 and 3) shows they're really the same expression in disguise!

4³ = 64, 3⁴ = 81 → 3⁴ is greater 2⁸ = 256, 8² = 64 → 2⁸ is greater 100² = 10,000, 2¹⁰⁰ ≈ 1.27 × 10³⁰ → 2¹⁰⁰ is FAR greater

Don't assume the bigger base always wins — the size of the EXPONENT usually matters much more, especially as numbers grow!

10⁹ + 10⁹ = 2×10⁹ — you ADD separate populations together (multiplying would give the wrong, absurdly large 10¹⁸, which makes no real-world sense here)!

36⁵ = 60,466,176 possible passcodes
1,000,000 ÷ 86,400 seconds/day ≈ 11.6 days old

A million seconds is barely more than a week and a half! But a BILLION seconds is about 31.7 years — that's the wild jump from million to billion.

9

Puzzle time! Tremendous in Ten

Grab a partner (a sibling, a friend, anyone!) and play this speed-thinking game from the book.
📖 How to play

In just 10 seconds, each player writes a number or expression using only the digits 0–9 and arithmetic operations. The person whose number/expression gives the LARGER value wins the round!

🎲 Round 1 example

Roxie wrote 10000000000000 and Estu wrote 999999 × 999999. Who wins?

Roxie's number = 10¹³ (13 zeros) Estu's number < (10⁶)² = 10¹² (since 999999 < 10⁶)
Roxie wins! Her 10¹³ beats Estu's number, which is less than 10¹².

Roxie's sum is only about 4 × 10¹⁰⁰⁰ — still "sized" like 10¹⁰⁰⁰ (adding four copies barely changes the size of such a huge number). Estu's number has exponent 1,000,000 — a MUCH bigger power of 10, multiplied by a modest 9000.

Estu wins by an enormous margin — 10¹⁰⁰⁰⁰⁰⁰ dwarfs 10¹⁰⁰⁰ (a million-digit exponent versus a thousand-digit one)!

Try these house-rule variations for extra rounds:

  • Exponents NOT allowed — only addition allowed.
  • Exponents NOT allowed — addition and multiplication allowed.
  • Exponents ARE allowed — only addition allowed.
  • Exponents ARE allowed — any arithmetic operation allowed.

Make up your own rules, or play with more people at once!

10

Practice like the real exam

Section A (12 MCQ, 1 mark), B (10 × 2 marks), C (8 × 3 marks), D (4 × 4 marks), E (2 case studies, 4 marks). Here's a taste of each.

Section A · MCQ (1 mark each)

(b) 1

(b) 1 ≤ x < 10

Section B · short answer (2 marks each)

(i) 10⁻² × 10⁻⁵ = 10⁻⁷ (ii) 5⁷ ÷ 5⁴ = 5³ = 125 (iii) 9⁻⁷ ÷ 9⁴ = 9⁻¹¹ (iv) (13⁻²)⁻³ = 13⁶ = 4,826,809 (v) m⁵n¹²(mn)⁹ = m⁵n¹² × m⁹n⁹ = m¹⁴n²¹

Section C · longer answer (3 marks each)

Every time you move the decimal point in the base by one place, the SQUARE's decimal point moves by TWO places (since it's squared):

(1.2)² = 1.44 (0.12)² = 0.0144 (0.012)² = 0.000144 120² = 14,400

Section D · 4 marks each

(i) Clothing items:

8.2 × 10⁹ × 30 = 246 × 10⁹ = 2.46 × 10¹¹ clothing items

(ii) Honeybees (100 million colonies = 10⁸, 50,000 bees each):

10⁸ × 50,000 = 10⁸ × 5×10⁴ = 5.0 × 10¹² honeybees

(iii) Bacterial cells worldwide (38 trillion per person, ≈8.2×10⁹ people):

38 × 10¹² × 8.2 × 10⁹ = 311.6 × 10²¹ = 3.116 × 10²³ bacterial cells

(iv) Lifetime eating time (assume ~70-year lifespan, ~1 hour of eating per day):

1 hour/day = 3600 seconds/day Total = 3600 × 365 × 70 = 91,980,000 seconds ≈ 9.198 × 10⁷ seconds

1 arab / 1 billion seconds = 1×10⁹ ÷ 86,400 seconds-per-day ≈ 11,574 days ≈ 31.7 years.

1,000,000,000 seconds ÷ 86,400 s/day ≈ 11,574.1 days 11,574 days before 30 Aug 2026 ≈ 21 December 1994

So exactly 1 billion seconds before today (30 August 2026) lands on approximately 21 December 1994 — the book's official answer just says "≈31.7 years ago," so this is our best-effort exact date working from today.

Section E · case study (4 marks)

(a) With repeats allowed: 10⁵ = 1,00,000 codes.

(b) All-different digits: 10×9×8×7×6 = 30,240 codes.

(c) Repeats-allowed (10⁵) is MORE secure — it gives far more possible codes (1,00,000 vs 30,240), making it harder to guess.

11

You did it! 🎉

Chapter 2 done — you now command every law of exponents, know why doubling paper 46 times reaches the Moon, can name numbers up to a maha shankh, and can estimate almost ANYTHING using powers of 10! ⭐
Exponential notation Product & quotient rules Power of a power Zero & negative exponents Scientific notation Powers of 10 & place value Fermi estimation Big number sense Number-naming history

🏁 Chapter 2 of 7 · Term 1 Maths · Prishita, Class 8